Grep pattern all character1/16/2024 ![]() Here, the array holds all matches of the regex (a quote, followed by as many non- " as possible until the next "). grep -F '(printf '\r')' application. To do it with a single command, you could use one of: To grep for carriage return, namely the \r character, or 0x0d, we can do this: grep -F '\r' application.log Alternatively, use printf, or echo, for POSIX compatibility. Personally, I'd probably just do $ grep -oP '"+"' file | tr -d '"'īut that is two commands. the second is here" as being inside quotes. And all of the quoted words are in separate lines and they are not expanded to multi lines.įirst of all, your grep -Po '"\K*' file idea fails because grep sees both "One" and ". and also my files contain nested quotes like "foo "bar" zoo". regexpr (), gregexpr (): Search a character vector for regular expression matches and return the indices where the match begins useful in conjunction with regmatches (). grep (), grepl (): Search for matches of a regular expression/pattern in a character vector. Reply to comments: It's not important for me to removing whitespace around matched pattern inside a pair of quotes, but it would be better if the command support it too. The primary R functions for dealing with regular expressions are. How can I achieve/print all of my patterns just using one command? e.g: below command grep -oP '"*"' file | grep -oP '*' But I'm looking for one command and without using that for multiple time. I know I can do this with multiple commands combination. You need to anchor the pattern in an appropriate way to get around that. But these patterns are all contained within the string 'aaaa', which is why it turns up in your results. If you think of this with the letter 'a', you're trying to catch 'a', 'aa' & 'aaa'. the second is here "Two "Īnd here are in second line " Three " "Four". 1 Just a brief note regarding your problem. For example it works if my input file contains the following: first matched is "One". What I tried, is this command: grep -Po ' "\K*' fileĪbove command works fine if I have a space before first pair of " marks. ![]() the second is here"Two "Īnd here are in second line" Three ""Four".Īs you can see all strings in output are between a pair of quotes. Let say I have a file with contents look like as following: first matched is "One". I'm trying to find all patterns between a pair of double quotes. ![]()
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